2x^2+200=-40x

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Solution for 2x^2+200=-40x equation: 



2x^2+200=-40x

We move all terms to the left:

2x^2+200-(-40x)=0

We get rid of parentheses

2x^2+40x+200=0

a = 2; b = 40; c = +200;
Δ = b2-4ac
Δ = 402-4·2·200
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{4}=-10$

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